From the experiment performed we get,

Current = 1.406 A

Voltage = 127 V

W1 = 0.133 W

W2 = 0.270 W

We are to calculate the following values.

1. No load power factor (cos φ₀) = ω₀  /  √3  V₀ l₀

2. l_ω = l₀ cos φ₀ /  √3

3. Working component of current l_m = l₀ sin φ₀ /  √3

4. No load resistance = R₀ = V₀ /I_w

5. No load reactance = X₀ = V₀ /I_m

W0 = W1 + W2 = 0.403 W

1. cos φ₀=0.403/309.27 = 0.0013

Therefore φ₀ = 89.9⁰

l_ω = l₀ cos φ₀ /  √3

=(1.406 x 0.0013)/1.732
=0.001 A

3. I_m = 1.406 x sin 89.9^o

0.81 A

4. R₀ = V₀ /I_w

127/0.001=127000 Ω

5. X₀ = V₀ /I_m

127/0.81 = 156.79 Ω